<html><body style="word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-space; ">Chris<div><br></div><div>Please send a drawing. I'm the type that needs to have a clear picture of it! a little slow on the circuit side...</div><div>From what I was told it remains 12vdc</div><div><br></div><div>Best</div><div>alex</div><div><div><div>On May 28, 2008, at 1:11 PM, Chris Vecchio wrote:</div><br class="Apple-interchange-newline"><blockquote type="cite"><br>It's weird that there's no current spec for the open collector output.<br><br>A relay should do the trick however and you're right that you will <br>need a diode to protect the PIR sensor from the relay's inductive kick.<br><br>I can send you a schematic of how to do it if you want.<br> <br> - Chris<br><br> <table class="readtext" border="0" cellpadding="1" cellspacing="7"><tbody><tr><td bgcolor="#789be0"><div style="width: 1px;"> </div><br></td><td>-------Original Message-------<br> From: Alexander Makenzie <alex.makenzie@gmail.com><br> Subject: [dorkbotnyc-blabber] Circuit Help<br> Sent: 28 May '08 16:54<br> <br> Hello<br> <br> I am trying to figure out how to make this PIR sensor work that I just <br> bought with another component I need to use.<br> <br> data sheet:<br> <a href="http://www.electronics123.net/amazon/datasheet/kc7786.pdf" mce_href="http://www.electronics123.net/amazon/datasheet/kc7786.pdf" target="_blank" style="text-decoration: underline;">http://www.electronics123.net/amazon/datasheet/kc7786.pdf</a><br> <br> Basically, I light electroluminescent panels with these special high <br> frequency transformers, they run on 12vdc. I have been running them <br> using this 12vdc wall transformer, it is regulated a 1 amp with no <br> problem. However when I connect the PIR sensor the output voltage <br> becomes 12vdc at .2 amps and this is too low to drive the transformer <br> and therefore won't turn the light on.<br> <br> So, I need the slightest boost. It has been suggested to me to use a <br> relay. This is where my confusion begins. I have been reading about <br> them, I understand the premise, but I only need a slight bump up of <br> the amperage not voltage.<br> <br> I have also been advised that due to the sensitivity of this PIR <br> circuit I'll need to protect it from the electro magnetic pulse <br> discharged from the relay when switching off.<br> <br> Can anyone help me here?<br> <br> Thank You!<br> Alex<br> <br> --<br> <br> <a href="http://www.alexmakenzie.com">www.alexmakenzie.com</a><br> ........................................................................<br> .........dorkbot: people doing strange things with electricity..........<br> ..........................<!-- <a href="http://dorkbot.org............................" mce_href="http://dorkbot.org............................" target="_blank" style="text-decoration: underline;"> --><a href="http://dorkbot.org">http://dorkbot.org</a>............................<!-- </a> --><br> ........................................................................<br> </alex.makenzie@gmail.com></td></tr></tbody></table> ........................................................................<br>.........dorkbot: people doing strange things with electricity..........<br>..........................<a href="http://dorkbot.org">http://dorkbot.org</a>............................<br>........................................................................<br></blockquote></div><br></div></body></html>