tough to explain the subject...

[Bram De Jong]

Hi,


quite a while ago someone told me about a method to 'softly' go from one
value to the other:

v from a to b in N steps:

initialise:
	v = a
	dv = 0
	ddv = c1
	const = c2

loop
	v += dv
	dv += ddv
	ddv += const

The trick is to set the right c1 and c2 (as the person said).
Well, I've been tinkering around with some equations, but I just can't
find it!!!
I've come as far as
	c1 = 6*(b-a)/(N*N)
	c2 = -12*(b-a)/(N*N*N)
But, it doesn't seem to work.
I've approched the problem via f(x)=ax**3 + bx**2 + cx + d but as it seems
the conversion from the continuous problem (df/dx, ...) to the discrete
problem makes my equations fail.

Can anybody help me?


Bram

<I ****think**** that it was Phil Burk who told me the method, but I am
NOT shure>




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